A pot with steel bottom 8.5mm thick rest on hot stove. The area of the bottom of the pot is 0.15m2. The water inside the pot is a 100 0c and 390gm of water is evaporated every 3 minute. Find the temperature of lower surface of the pot which is in contact with the stove.

 

A pot with steel bottom 8.5mm thick rest on hot stove. The area of the bottom of the pot is 0.15m². The water inside the pot is a 100 ⁰c and 390gm of water is evaporated every 3 minute. Find the temperature of lower surface of the pot which is in contact with the stove.

Ans:-

                   Given:
                             thickness of steel (x) = 8.5 mm = 8.5 x 10^-3m
                             area (A) = 0.15m²
                             inside tmp^r (θ₂) = 100⁰C
                             outside tmp^r (θ₁) =?
                             Mass of water (m) = 390gm = 0.39Kg
                             time of heat flow (t) = 3 min = 180 sec
                             thermal conductivity (K) = 50.2 wm^-1k^-1
                             latent heat of vaporization (L_v) = 2256 x 10³J/kg

Here,
formula for rate of change of heat,

                             

Therefore, the temperature of the lower surface of the pot which is in the contact with the stove is 105.517⁰C.

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